Bug 48630 – ES5 Strict mode: OctalEscapeSequence in string literals

• Status: RESOLVED
• Resolution: INVALID
• Component: JavaScriptCore

[Asen Bozhilov]

I have used the follow test case: 

/**
 * A conforming implementation, when processing strict mode code (see 10.1.1), may not
 * extend the syntax of EscapeSequence to include OctalEscapeSequence as described in B.1.2.
 */

var testDesc = 'EscapeSequence cannot include OctalEscapeSequence: ';
try {
    eval('"use strict"; "\101";');
    util.printLine(testDesc + 'FALSE'); 
} catch (e) {
    if (e instanceof SyntaxError) {
        util.printLine(testDesc + 'TRUE'); 
    }
    else {
        util.printLine(testDesc + 'UNDEFINED BEHAVIOR');
    }
}

[Oliver Hunt]

Hahah, i just worked out why this is passing, and why that is correct behaviour.
You have an octal escape in:
eval('"use strict"; "\101";');

The escape is parsed in the context of the function containing eval, so eval sees
"use strict"; "A";

as its input.

The test should be
eval('"use strict"; "\\101";');

Which throws a syntax error as expected.

Thanks for these bug reports by the way :D