We can save both CPU and memory by reducing the tile coverage area for non-visible pages.
Created attachment 299270 [details] Patch
<rdar://problem/30105774>
Comment on attachment 299270 [details] Patch View in context: https://bugs.webkit.org/attachment.cgi?id=299270&action=review Please add a test. You can dump the layer tree including tile caches (LAYER_TREE_INCLUDES_TILE_CACHES). I don't know how to make something not visible (if there isn't a way, add one!). > Source/WebCore/page/FrameView.h:583 > void show() final; > + void hide() final; Names so bad (they sounds imperative). > Source/WebCore/rendering/RenderLayerBacking.cpp:206 > + if (!backing->owningLayer().renderer().page().isVisible()) Is it cheaper to get to Page via frameView?
Created attachment 306684 [details] Proposed patch
r=me
Comment on attachment 306684 [details] Proposed patch Clearing flags on attachment: 306684 Committed r215181: <http://trac.webkit.org/changeset/215181>
All reviewed patches have been landed. Closing bug.