Summary: | ParallelHelperPool::runFunctionInParallel() shouldn't allocate, and ParallelHelperPool.h shouldn't be included everywhere | ||||||
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Product: | WebKit | Reporter: | Filip Pizlo <fpizlo> | ||||
Component: | JavaScriptCore | Assignee: | Filip Pizlo <fpizlo> | ||||
Status: | RESOLVED INVALID | ||||||
Severity: | Normal | CC: | benjamin, cmarcelo, commit-queue | ||||
Priority: | P2 | ||||||
Version: | Other | ||||||
Hardware: | All | ||||||
OS: | All | ||||||
Bug Depends on: | 149671 | ||||||
Bug Blocks: | 149432 | ||||||
Attachments: |
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Description
Filip Pizlo
2015-09-29 11:29:55 PDT
Created attachment 262084 [details]
the patch
Comment on attachment 262084 [details]
the patch
r=me
Landed in http://trac.webkit.org/changeset/190324 I suspect that this caused flaky crashes, rdar://problem/22916304 Re-opened since this is blocked by bug 149671 (In reply to comment #4) > I suspect that this caused flaky crashes, rdar://problem/22916304 Yeah, this needs to be rolled out, and I believe that I understand now why the patch is wrong. The observation behind this patch is that the task cannot run again after runFunctionInParallel returns. That's true. But the way that ParallelHelperPool::helperThreadBody works, it will notify runFunctionInParallel that it's no longer going to run the task *before* it derefs the task. The sequence is: 1) get a task and ref it. 2) run the task. 3) notify task complection. ---> at this point, runFunctionInParallel can return. 4) deref the task. ---> at this point, the helper thread body will crash if runFunctionInParallel returned. We could still find other ways to avoid allocating the task. But I think that it's not worth it if it will be complicated. The easiest mental model is to treat the task as a proper ref-counted object, in which case a stray RefPtr referencing the task after it cannot run anymore is fine. If we wanted to allow stack-allocation of the task, then we'd have to change our mental model to: it's illegal to have a RefPtr to the task after we have consensus that the task cannot run anymore. I don't want to have to think that hard about this code. |